Question

find the roots of the following quadratic X2-3√5x+10=0​

Answer 1

10=2√5* √5

and 2√5+√5=3√5

now x2-(2√5+√5)x+10=0

x2-2√5x-√5x+10=0

x(x-2√5)-√5(x-2√5)=0

(x-2√5)(x-√5)=0

therefore x=2√5

or x=√5

MARK BRAINLIEST.

Answer 2

Solution==>>

x²-3√5+10=0

(applying middle term splliting method)

x²-2√5x-√5x+10=0

x(x-2√5)-√5(x-2√5)=0

(x-2√5)(x-√5)=0

x-2√5=0 , x-√5=0

x=2√5 , √5

Answer...