Math, asked by pavanisaipala9602, 8 months ago

Find the roots of the following Questions vi) 2x2−19x+42=0

Answers

Answered by valanraj

1

Answer:

x = 6, 7/2

Step-by-step explanation:

2x^2 - 19x + 42 = 0

(2x - 7) (x - 6) = 0

2x -7 = 0. x-6 = 0

2x = 7. x = 6

x = 7/2

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