Find the roots of the following Questions vi) 2x2−19x+42=0
Answers
Answered by
1
Answer:
x = 6, 7/2
Step-by-step explanation:
2x^2 - 19x + 42 = 0
(2x - 7) (x - 6) = 0
2x -7 = 0. x-6 = 0
2x = 7. x = 6
x = 7/2
Similar questions