Question

find the roots of the following square equation by factorizatim. abx2+(b2-ac)x-bc=0​

Answer 1

Answer:

Given: abx

2

+(b

2

−ac)x−bc=0

Factorizing the given equation,

⟹abx

2

+b

2

x−acx−bc=0

⟹bx(ax+b)−c(ax+b)=0

⟹(bx−c)(ax+b)=0

Solving the above equation for x, we get

⟹(bx−c)=0 or (ax+b)=0

⟹x=

b

c

or x=

a

−b