Question

find the roots of the following x2+x-p(p+1)=0 , where p is a constant

Answer 1

Answer:

Step-by-step explanation:

p + (- p - 1) = -1 and p(- p - 1) = -p(p + 1)

then the roots are p and - p - 1.

Answer 2

Answer:-p-1, p

Step-by-step explanation:

x2+x-p(p+1)=0

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, p