Question

Find the roots of the given equation.

4x² + 4√3x + 3 = 0

Answer 1

$\underline {\small {\bold {ANSWER :}}}$

$\small {\bold{By\: using\: mid \:term\: split \:method}}$ -

4x² + 4√3x + 3 = 0

4x² + 2 √3x + 2√3 x + 3 = 0

2x ( 2x +√3 ) + √3 ( 2x +√3 ) = 0

( 2x +√3 )( 2x +√3 ) = 0

( 2x +√3 ) = 0, ( 2x +√3 ) = 0

=> - √3 / 2

Answer 2

Answer: -0.866

Step-by-step explanation:

use (-b±√(b²-4ac))/2a.

insert a = 4, b = 4√3, c = 3

Answer: -0.866