Find the roots of the given equation, where m is a constant
x^2 -3x-m(m+3)=0
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Given: equation x2+x−p(p+1)=0, where p is a constant
To find the roots of the equation
Sol: the given equation is of form ax2+bx+c=0∴a=1,b=1,c=−p(p+1)
We know the roots of the equation can be find out using the formula,
x=2a−b±b2−4ac
Substituting the values of a, b, c, we get
x=2−1±12−4(1)(−p(p+1)x=2−1±1+4p2+4px=2−1±(2p+1)
or x=2−1+(2p+1),x=2−1−(2p+1)
⇒x=p,x=−(p+1) are the roots of the given equation.
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