Math, asked by aniketagrawalujjain, 1 month ago

find the roots of the given quadratic equation.
2x² - x + 1/8 = 0​

Answers

Answered by Anonymous
8

Answer :

  • 1/4 and 1/4

Given :

  • 2x² - x + 1/8 = 0

To find :

  • Roots of Qudratic equation

Solution :

➺ 2x² - x + 1/8 = 0

Multiplying LHS RHS by 8

➺ 16x² - 8x + 1 = 0

➺ 16x² - 4x - 4x + 1 = 0

➺ 4x(4x-1) - 1(4x - 1) = 0

➺ (4x - 1) (4x - 1) = 0

➺ 4x - 1 = 0 or 4x - 1 = 0

➺ 4x = 1 or 4x = 1

➺ x = 1/4 or x = 1/4

x = 1/4 and x = 1/4

More Explanation:

  • Qudratic equation is nothing but an equation that can be written in standard form
  • ax² + bx + c = 0
Answered by Anonymous
0

Answer:

Answer :

1/4 and 1/4

Given :

2x² - x + 1/8 = 0

To find :

Roots of Qudratic equation

Solution :

➺ 2x² - x + 1/8 = 0

Multiplying LHS RHS by 8

➺ 16x² - 8x + 1 = 0

➺ 16x² - 4x - 4x + 1 = 0

➺ 4x(4x-1) - 1(4x - 1) = 0

➺ (4x - 1) (4x - 1) = 0

➺ 4x - 1 = 0 or 4x - 1 = 0

➺ 4x = 1 or 4x = 1

➺ x = 1/4 or x = 1/4

x = 1/4 and x = 1/4

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