Find the roots of the polynomial 2 x^3+ 3 x ^2 - 11 x-6
Answers
Answered by
0
Step-by-step explanation:
The given polynomial is
2x^3+3x^2-11x-62x
3
+3x
2
−11x−6
According to rational root theorem, all possible rational roots are in the form p/q where, p is factor of constant and q is factor of leading term.
In the given polynomial constant term is -6.
Factors of -6 are ±1, ±2, ±3, ±6.
In the given polynomial leading term is 2.
Factors of 2 are ±1, ±2.
All possible rational roots are
\pm1, \pm 2,\pm 3,\pm 6,\pm \dfrac{1}{2},\pm \dfrac{3}{2}±1,±2,±3,±6,±
2
1
,±
2
3
#Learn more
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 5x3 – 7x + 11?
Answered by
3
Answer:
Roots of polynomials:-
- 2x³ = √2x³ = 2x²
- 3x² = √3x² = 3x
- -11x-6 = √11x-6
Similar questions