Math, asked by iloveselena9278, 7 months ago

Find the roots of the polynomial 2 x^3+ 3 x ^2 - 11 x-6

Answers

Answered by manishamalik384
0

Step-by-step explanation:

The given polynomial is

2x^3+3x^2-11x-62x

3

+3x

2

−11x−6

According to rational root theorem, all possible rational roots are in the form p/q where, p is factor of constant and q is factor of leading term.

In the given polynomial constant term is -6.

Factors of -6 are ±1, ±2, ±3, ±6.

In the given polynomial leading term is 2.

Factors of 2 are ±1, ±2.

All possible rational roots are

\pm1, \pm 2,\pm 3,\pm 6,\pm \dfrac{1}{2},\pm \dfrac{3}{2}±1,±2,±3,±6,±

2

1

2

3

#Learn more

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 5x3 – 7x + 11?

Answered by adarsh262544
3

Answer:

Roots of polynomials:-

  1. 2x³ = √2x³ = 2x²
  2. 3x² = √3x² = 3x
  3. -11x-6 = √11x-6
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