find the roots of the quadrantic equation x2-7x+12=0
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Answers
Step-by-step explanation:
x2-4x-3x+12=x(x-4)-3(x-4)=(x-3)(x-4) hence x=3orx=4
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Answer:
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Step-by-step explanation:
Roots are that values of variables in the equation which satisfy the given equation .
We can find the roots by the process of factorization
Two main ways of factorization :-
1) Splitting middle term
2) Using Baudhayan formula
We are going to use method 1 here :-
Given equation :- x^2 - 7x + 12 = 0
→ x^2 - 4x - 3x + 12 = 0
→ x(x-4) - 3( x - 4 ) = 0
→ ( x - 3 ) ( x - 4 )= 0
→ ( x - 3 ) = 0. or , ( x - 4 ) = 0
→ x = 3 or , x = 4
Hence , the required roots of the given equation are 3 and 4 .............
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