Find the roots of the quadratic equation 2/5x^2-x-3/5=0
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2x² / 5 - x/1 - 3/5 = 0
By Taking LCM ,
2x² - 5x - 3 = 5* 0
2 x² - 5x - 3 = 0
By Prime factorisation { (2x²) * (-3)= -6x² , also -6x ² = - 6x * 1 x , and -6x + 1x = -5x }
2 x² - 6x + 1 x + 3 = 0
2x ( x -3 ) +1 ( x + 3 ) = 0
(2x+1 ) ( x - 3 ) = 0 2x + 1 = 0
or x -3 = 0 x = - 1 / 2 or x = 3 x = - 1 / 2 and 3 are ROOTS of above quadratic equation.
SmãrtyMohït:
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