Question

find the roots of the quadratic equation 2/5x2-x-3/5=0​

Answer 1

Explanation:

Given,

⇒ 2x2 - 5x – 3 = 0

By splitting the middle term,

⇒2x2 - 6x + x – 3 = 0

Taking common in the expression,

⇒2x (x - 3) + 1 (x - 3) = 0

⇒ (2x + 1) (x - 3) = 0

⸫ 2x + 1 = 0 and x – 3 = 0

⸫ x=-1/2 and x=3

Answer 2

Answer:

x= -3/2 or x= -1

Step-by-step explanation:

$\frac{2}{5} {x}^{2} - x - \frac{3}{5} = 0 \\ \frac{2}{5} {x}^{2} - x = \frac{3}{5} \\ 2 {x}^{2} - x = 3 \\ 2 {x}^{2} - x - 3 = 0 \\ 2 {x}^{2} + 2x - x - 3 = 0 \\ 2x(x + 1) - 3(x + 1) = 0 \\ (x + 1) = 0 \: or \: (2x - 3) = 0 \\ x - 1 \: or \: x = \frac{ - 3}{2}$