Find the roots of the quadratic
equation 224 x = 4 c0' by using
suitable formula.
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Answer:
2a^5- 54 a²
=2 a²( a³- 27 )
= 2 a² [ a³-3³ ]
We know that,
x³ - y³= ( x - y ) ( x²+ xy + y² )
= 2 a² ×( a - 3 ) ( a²+3a+3² )
=2a²(a-3)(a²+3a+9)
Hope it helps...
Step-by-step explanation:
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