Question

Find the roots of the quadratic equation 25x2-10ax+a2-16b2=0 by using factorization.​

Answer 1

Answer:

25x²-10x+a²-16b²

D=b²-4ac

D=(-10a)²-4(25)(a²-16b²)

D=100a²-100a²+1600b²

D=1600b²

x=(-b+√D)/2a , (-b-√D)/2a

x= {-(-10a)+√1600b²}/2(25) , {-(-10a)-√1600b²}/2(25)

x= (10a+40b)/2 , (10a-40b)/2

x= 5a+20b , 5a-20b

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