Question

Find the roots of the quadratic equation 2x^2 +5/3x+2=0 by factorisation
...........please give me ans fast

Answer 1

Answer:

x=3/2 or x=-2/3

Step-by-step explanation:

2x^2 + 5/3x + 2=0

to eliminate 3 in denominator,multiply all terms by 3

we  get,

6x^2 +5x + 6= 0

to factorise take 6*6=36 (first and last term)

now we need to find a 2 numbers which when multiplied gives 36 and when added or sub gives midterm 5

2 * 18= 36 but 2+18=20 and 2-18=16(NO)

3 * 12= 36 but 3+12=15 and 3-12=9(NO)

4*9=36 and 9-4= 5

hence the terms are 4 and 9

rewrite equ as 6x^2 -4x + 9x + 6=0

now considering (1st nd 2nd term) and (3rd and 4th term) take common out

2x(3x-2) -3(3x-2)=0

hence we get 2 equ

2x-3=0 and 3x -2=0

hence x=3/2 or x=2/3

Hope this helps!!!