Question

find the roots of the quadratic equation 2x^2-7x+3=0​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ 2 {x}^{2} - 7x + 3 = 0 \\ a = 2 \\ b = - 7 \\ c = 3 \\ \\ x = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{7 + \: or \: - \sqrt{49 - 24} }{2(2) } \\ x = \frac{7 + \: or \: -5 }{4} \\ x = 3 \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: \: x = \frac{1}{2}$

Answer 2

2x²-7x+3 = 0

=> 2x²-6x-x+3 = 0

=> 2x(x-3)-1(x-3) = 0

=> (2x-1)(x-3) = 0

Roots : 1/2 and 3

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