Question

Find the roots of the quadratic equation (2x+4)²=5

Answer 1

Answer:

$(2x + 4) ^{2} = 5 \\ \\ using \: formula \\ \\ (a + b) ^{2} = a ^{2} + 2 ab + b ^{2} \\ \\ so \: (2x) ^{2} + 2 \times 2x \times 4 + (4) ^{2} = 5 \\ \\ = > 4x ^{2} + 16x + 16 = 5 \\ \\ = > 4x^{2} + 16x + 16 - 5 = 0 \\ \\ = > 4x^{2} + 16x + 11 = 0$

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