Question

Find the roots of the quadratic equation 2x^+x-4=0 by using suitable formula.​

Answer 1

Step-by-step explanation:

Given Question:-

Find the roots of the quadratic equation 2x^+x-4=0 by using suitable formula.

Correction:-

2x^2+x-4=0

Solution:-

Given quardratic equation is 2x^2+x-4=0

On Comparing this with the standard quadratic equation ax^2+bx+c = 0

We have ,

a = 2

b= 1

c= -4

We know that

Sridharacharya formula

x = [-b±√(b^2-4ac)]/2a

On Substituting these values in the above formula then

=> x = [-1±√{(1)^2-4(2)(-4)}]/2(2)

=> x = [-1±√(1+32)]/4

=>x = [-1±√33]/4

x = (-1+√33)/4 and (-1-√33)/4

Answer:-

The roots of the given quardratic equation are

(-1+√33)/4 and (-1-√33)/4

Used formula:-

Sridharacharya formula:-

x = [-b±√(b^2-4ac)]/2a