Question

find the roots of the quadratic equation:- 2x² - 3x - 6 = 0​

Answer 1

Answer:

[ 3 ± √57] / 4

Step-by-step explanation:

2x² - 3x - 6 = 0​

Using Quadratic formula,

x =[ -b ± √(b² - 4ac) ]/ 2a

x = [-(-3) ± √(-3)² - 4(2)(-6)] / 2(2)

x = [ 3 ± √(9 + 48) ] / 4

x = [ 3 ± √57] / 4

$x=\frac{3+\sqrt{57} }{4}$

$x=\frac{3-\sqrt{57} }{4}$