Question

find the roots of the quadratic equation 2x²-7x+3=0​

Answer 1

Answer:

Step-by-step explanation:

2x^2-7x+3

2x^2-6x-x+3

2x(x-3)-1(x-3)

(2x-1)(x-3)

x=1/2,3

Answer 2

Answer:1/2,3

Step-by-step explanation:

2x^2-7x+3=0

2x^2-(6+1)x+3=0

2x^2-6x-x+3=0

2x(x-3)-1(x-3)=0

(2x-1)(x-3)=0

2x-1=0, X-3=0

X=1/2, X=3(answer)

Hence the roots are 1/2 and 3.