Math, asked by pleasenymgyf, 2 months ago

Find the roots of the quadratic equation 2x2 – 7x + 3 = 0 using completing the square  method.​

Answers

Answered by nagamaheswari
0

2x² -7x +3=0

2(x² -7/2x) +3=0

2(x² -2 × 7/4x +49 /16 ) =49/8 - 3 = 25/8

(x - 7/4 )² = -7/4 = 5/4

x= -7/4 =5/4.

Answered by Anonymous
53

Question:-

Find the roots of the quadratic equation 2x2 – 7x + 3 = 0 using completing the square  method.

Solution:-

{2x}^2-{7x+3=0}

=> {2(x^2-\frac{7}{2}x)}+3=0

=> {2(x^2-2×\frac{7}{4}x+\frac{49}{16})}=\frac{49}{8}-3=\frac{25}{8}

{(x-\frac{7}{4})}^2=\frac{25}{16}=>{x-\frac{7}{2}}=+\frac{5}{4}

=> x=\frac{7}{4}+\frac{5}{4}=3 or\frac{1}{2}

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