Question

find the roots of the quadratic equation 3 x square - 2 under root 6 X + 2 is equal to zero​

Answer 1

$3x {}^{2} - 2 \sqrt{6} x + 2 = 0 \\ = > 3x {}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0 \\ = > \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) = 0 \\ = > ( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) = 0 \\ = > \sqrt{3} x - \sqrt{2} = 0 \\ = > \sqrt{3} x = \sqrt{2} \\ = > x = \frac{ \sqrt{2} }{ \sqrt{3} } \: \: \: and \: again \: same \: value \\ x = \frac{ \sqrt{2} }{ \sqrt{3} }$

I hope that helps you

Answer 2

Answer:

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