Question

find the roots of the quadratic equation 3x^2-14x+8​

Answer 1

Answer:

3X^2-14X+8

3X^2-12X-2X+8

3X(X-4)-2(X-4)

(X-4)(3X-2)

so,  X = 4 0R 2/3

Step-by-step explanation:

Answer 2

Answer:

Roots = x = 2/3 , 4

Step-by-step explanation:

sum = -14

product= 8*3=24

So, 3x²-14x+8

= 3x²-12x-2x+8

=3x(x-4)-2(x-4)

=(3x-2)(x-4)

Therefore ,x=2/3,4