Find the roots of the quadratic equation 3x^2-2√6x+2=0 by factorization method
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3x²-2√6x+2=0
by splitting we get
3x²-√6x-√6x+2=0
√3x(x-√2)-√6(x-√2)=0
(√3x-√6)(x-√2)=0
(√3x-√6)=0 or (x-√2)=0
so we get
x=√2 and x=√2
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Sreekuttan1246:
Thanks,it helps in my work
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