Question

Find the roots of the quadratic equation 3x^2-2√6x+2=0 by factorisation method.

Answer 1

Hope this answer will help you...

Answer 2

Hi friend ✋✋✋✋
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Your answer
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3x^2 - 2√6x + 2 = 0

=> 3x^2 - √6x - √6x + 2 = 0

=> √3x(√3x - √2) - √2(√3x - √2) = 0

=> (√3x - √2)(√3x - √2) = 0

=> (√3x - √2) ^2 = 0

=> √(√3x - √2)^2 = √0

=> √3x - √2 = 0

=> √3x = √2

=> x = √2/√3

rationalising, x = √6/3

Thus , √6/3 is a root of the given polynomial.

HOPE IT HELPS