find the roots of the quadratic equation 3x-2√6x+2=0
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Step-by-step explanation:
3 x^{2} -2√6x+2=0
3 x^{2} -√6x-√6x+2=0
√3 x^{2} *√3 x^{2} -√3x*√2x-√3x*√2x+√2*√2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3
Therefore the equation has two equal roots; √2/√3
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