find the roots of the quadratic equation √3x square- 2x -√3
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√3x²-2x-√3
√3x²-3x+x-√3 as 2x can be written as -3x +x
√3x(x-√3)+1(x-√3) also 3 can be written as √3×√3 so that √3 could be taken out common
(√3x+1)(x-√3)
∴√3x+1=0 x-√3=0
√3x= -1 x=√3
x= -1/√3 x=√3
∴ the two zeroes of the polynomial √3x²-2x-√3 are -1/√3 and √3.
√3x²-3x+x-√3 as 2x can be written as -3x +x
√3x(x-√3)+1(x-√3) also 3 can be written as √3×√3 so that √3 could be taken out common
(√3x+1)(x-√3)
∴√3x+1=0 x-√3=0
√3x= -1 x=√3
x= -1/√3 x=√3
∴ the two zeroes of the polynomial √3x²-2x-√3 are -1/√3 and √3.
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