Find the roots of the quadratic equation : 3x²- 2 √ 6x+2=0
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3x²-2√6x+2=0
a=3, b= -2√6, c=2
D=b²-4ac
D=(-2√6)² - 4(3×2)
D=24-24
D=0, I.e √D=0
So we get that D=0, so the equation has 2 equal roots.
x=-b±√D×1/2a
x=-(-2√6)±0×1/6
x=2√6/6
x=√6/3 or x=-√6/3
a=3, b= -2√6, c=2
D=b²-4ac
D=(-2√6)² - 4(3×2)
D=24-24
D=0, I.e √D=0
So we get that D=0, so the equation has 2 equal roots.
x=-b±√D×1/2a
x=-(-2√6)±0×1/6
x=2√6/6
x=√6/3 or x=-√6/3
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