Question

find the roots of the quadratic equation 3x² +2√6x+ 2 = 0​

Answer 1

Answer:

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Step-by-step explanation:

3x^{2}x2 -2√6x+2=0

3x^{2}x2 -√6x-√6x+2=0

√3x^{2}x2 *√3x^{2}x2 -√3x*√2x-√3x*√2x+√2*√2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

x=√2/√3

Therefore the equation has two equal roots; √2/√3