Question

Find the roots of the quadratic equation 3x²-2√6x+2=0.

Answer 1

Answer:

3x² - 2√6x + 2 = 0  

a = 3 ; b = -2√6 ; c = 2  

We have  

▲ = b² - 4ac = (-2√6)² - 4.3.2 = 24-24 = 0  

=> Only one x  

=> x = -b / 2a = 2√6 / 3.2 = √6 / 3

Step-by-step explanation:

Answer 2

roots of the quadratic equation can be found as,

3x²-2√6x+2=0

the value of a is 3,

the value of b is -2√6

and the value of c is 2

the value of b can be written as -4.8989=-5

3x²-5x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

Either,                                         Or,

3x-2=0,                                        x-1=0,

x=2/3                                           x=1

so that the roots of quadratic equation have been found and it is either x=2/3 or x=1