Question

Find the roots of the quadratic equation 3x² - 2√6x + 2 = 0
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Answer 1

→Question: Find the roots of the quadratic equation 3x² - 2√6x + 2 = 0

→Solution:

• 3x² - 2√6x + 2
• 3x² - √6x - √6x +2                                ( -6√x - √6x = -2√6x)
• √3x(√3x-√2) - √2(√3x-√2)
• (√3x - √2)(√3x - √2) = 0

→Now:

• √3x - √2 = 0     for x = √⅔
• ∴The roots are √⅔,√⅔

Answer 2

Answer:

Given: 3x2−26x+2=0

3x2−6x−6x+2=0,3x(3x−2)−2(3x−2)=0

(3x−2)(3x−2)=0∴3x−2=0 or 3x−2=0

∴3x=2 or 3x=2,x=32

LHS =RHS