Question

Find the roots of the quadratic equation :
3x²- 2 √ 6x+2=0
Or
x : 3x²-2√6x+2=0

Answer 1

  3x² - 2√6x + 2 = 0 
a = 3 ; b = -2√6 ; c = 2 
We have 
▲ = b² - 4ac = (-2√6)² - 4.3.2 = 24-24 = 0 
=> Only one x 

=> x = -b / 2a = 2√6 / 3.2 = √6 / 3