Question

Find the roots of the quadratic equation 3x² - 26x + 2 = 0.​

Answer 1

Step-by-step explanation:

3x? – 2 v6 x + 2 = 0

We will factorize

using splitting the middle term method

3x? - V6 x - V6 x + 2 = 0

3x2 - V2 x 3 x - V2 x 3x + 2 = 0

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Splitting the middle term method

We need to find two numbers whose

Sum = - 2/6

Product = 2 x 3 = 6

Sum

-V6 & -V6 -26

3x? - (V2)(V3)x – (V2)(V3)x + 2 = 0 V3 x(V3x – v2) - vZ (V3x – V2) = 0

(73x - V2) (V3x - v2) = 0

V3x – V2 = 0

V3x = V2

X = 2 3 V3

V3x - 2 = 0

V3x = V2

X V3 3