Question

Find the roots of the quadratic equation 3x² - 2root6x+2=0
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Answer 1

Answer:

Hope this will be helpful !

Answer 2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀☆ G I V E N ⠀E Q U A T I O N : 3x² - 2√6x + 2

》 Let's Find out roots of Polynomial :

$\dashrightarrow \sf 3x^2 - 2\sqrt{6}x + 2 = 0 \\\\\dashrightarrow \sf 3x^2 - 2\sqrt{6}x + 2 = 0 \\\\ \dashrightarrow \sf 3x^2 - \sqrt{6}x - \sqrt{6}x + 2 = 0 \\\\ \dashrightarrow \sf \sqrt{3}x ( \sqrt{3}x - \sqrt{2}\:)\: - \sqrt{2}\:( \sqrt{3}x - \sqrt{2}\:)\: = 0 \\\\\ \dashrightarrow \sf ( \sqrt{3}x - \sqrt{2}\:)\:\:( \sqrt{3}x - \sqrt{2}\:)\: = 0 \\\\\dashrightarrow \sf x \:\:=\:\:\sqrt{\dfrac{2}{3}}\:\:or\:\:-\:\sqrt{\dfrac{2}{3}}\: \\\\ \dashrightarrow \:\:\underline {\boxed{\purple {\pmb{\frak{\: x \:\:=\:\:\sqrt{\dfrac{2}{3}}\:\:or\:\:-\:\sqrt{\dfrac{2}{3}}\:\:\:\:}}}}}$

$\qquad \therefore \:\:\underline { \sf Hence, \:The \:roots \:of \:Equation \:are \: \bf \sqrt{2/3}\:\:\sf \:or \:\bf -\sqrt{2/3}}$