Question

Find the roots of the quadratic equation: √3x2 - 2x -√3 = 0

Answer 1

Answer:

$3x {}^{2} - 2x - \sqrt{ {3}^{} }$

$\sqrt{}3x {}^{2} - 2x - \sqrt{}3 = 0$

$= > \sqrt{3}x {}^{2} - 3x + x - \sqrt{ {3}^{} } = 0$

$= > \sqrt{3}x(x - \sqrt{ {3}^{} }) + \\ 1(x - \sqrt{ {3}^{} }) = 0$

$= > (x - \sqrt{ {3}^{} })( \sqrt{ {3}^{} }x + 1) = 0$

∴ x = √3 , - 1/3

Step-by-step explanation:

@Dare