Question

find the roots of the quadratic equation 3x²-5x+2=0
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Answer 1

3x²-3x-2x+2=0

3x(x-1)-2(x-1)

(3x-2)(x-1)

when, 3x-2=0

x=2/3

when, x-1= 0

x=1

Answer 2

SoluTion:-

→ 3x²-5x+2 = 0

→ 3x²-3x-2x+2 = 0

→ 3x(x-1)-2(x-1) = 0

→ (3x-2)(x-1) = 0

→ x = 2/3 (or) 1

$✓$

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