Question

Find the roots of the quadratic equation :-

3x²-√6x+2=0​

Answer 1

Answer:

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Step-by-step explanation:

Given: 3x2−26x+2=0

3x2−6x−6x+2=0,3x(3x−2)−2(3x−2)=0

(3x−2)(3x−2)=0∴3x−2=0 or 3x−2=0

∴3x=2 or 3x=2,x=32 or x=