Question

Find the roots of the quadratic equation 4x² - 6√2x + 3 = 0 using quadratic formula

Answer 1

Step-by-step explanation:

We have,

$\rm 4x^2 -6\sqrt{2}x +3 =0$

$\rm x= \dfrac{-b±\sqrt{b^2-4ac}}{2a}$

$\rm x= \dfrac{-(-6\sqrt{2})±\sqrt{(-6\sqrt{2})^2-4(4)(3)}}{2(4)}$

$\rm x= \dfrac{6\sqrt{2}±\sqrt{72-48}}{8}$

$\rm x= \dfrac{6\sqrt{2}±\sqrt{24}}{8}$

$\rm x= \dfrac{6\sqrt{2}±2\sqrt{6}}{8}$