find the roots of the quadratic equation 5x^2-6x-2=0 check wheather the quadratic equation has real roots
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B^2-4ac
=36+40
=76
B^2-4ac is greater than zero .
So ,it will have real and distinct zeroes
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Answered by
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Answer:
5x^2 -6x -2=0
we check the discriminant b^2-4ac
here b= -6
a=5
c=-2
b^2-4ac =(-6) ^2 -4. 5.-2
= 36-40
=-4
Therefore it doesn't have any real roots
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