Question

find the roots of the quadratic equation 6 x square minus x minus 2 is equals to zero​

Answer 1

Answer:(2x+1) (3x-2)

Step-by-step explanation:

6x-x-2= 0

6x-4x+3x-2=0

2x(3x-2) +1(3x-2)=0

(2x+1) (3x-2)=0

First let's take (2x+1)

(2x+1)=0

2x = -1

x= -1/2 this is one root

Now take (3x-2)

(3x-2) =0

3x = 2

x=2/3 this is the other root .

Now the roots of the equation

are -1/2 & 2/3

Answer 2

Answer:

Step-by-step explanation

$6x^{2}-x-2=0\\\\=6x^-4x+3x-2=0\\=2x(3x-2)+1(3x-2)=0\\=(2x+1)(3x-2)$

Hence,

$2x+1=0\\\\2x=-1\\x=\frac{-1}{2}$

And

$3x-2=0\\3x=2\\x=\frac{2}{3}$

Therefore,x=$\frac{-1}{2}$ and $\frac{2}{3}$