Question

find the roots of the quadratic equation 6x^2-x-2=0 by the factoristion methods​

Answer 1

Answer:

-1/2 or 2/3

Step-by-step explanation:

$6x^{2} - x - 2 = 0$

We factorize it now,

$6x^{2} + 3x - 4x - 2 = 0\\3x(2x + 1) -2 (2x + 1)=0\\(2x + 1)(3x - 2) = 0$

(2x + 1) = 0 OR (3x-2) = 0

x = -1/2 or x = 2/3

Answer 2

Answer.:-

→ 6x² - x - 2 = 0

→ 6x² - 4x + 3x - 2 = 0

→ 2x ( 3x - 2 ) + 1 ( 3x - 2 ) = 0

→ ( 2x + 1 ) ( 3x - 2 ) = 0

→ 2x + 1 = 0 ‎ ‎ ‎; ‎ ‎ ‎ ‎ ‎ ‎3x - 2 = 0

→ 2x = - 1 ‎ ‎ ‎ ‎ ‎ ‎; ‎ ‎ ‎ ‎ ‎ ‎3x = 2

→ x = - 1/2 ‎ ‎ ‎ ‎ ‎ ‎; ‎ ‎ ‎ ‎ ‎ ‎x = 2/3

So the values of x are -1/2 and 2/3 .