Question

find the roots of the quadratic equation : 9x2-6x+1=0.​

Answer 1

Step-by-step explanation:

Use the quadratic formula

=−±2−4√2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

92−6+1=0

9x^{2}-6x+1=09x2−6x+1=0

=9

a={\color{#c92786}{9}}a=9

=−6

b={\color{#e8710a}{-6}}b=−6

=1

c={\color{#129eaf}{1}}c=1

=−(−6)±(−6)2−4⋅9⋅