Question

Find the roots of the quadratic equation 9x² -9 (a + b)x+ (2a² +5ab +2b²) = 0.​

Answer 1

Answer:

x =  2a + b / 3

or

x= a+ 2b / 3

Step-by-step explanation:

9x^2 - 9(a + b) x + (2a^2+ 5ab + 2b^2) = 0

9x^2 - 9(a + b)x + (2a + b) (a + 2b) = 0

9x^2 - 3(2a + b)x - 3 (a + 2b)x + (2a + b) (a + 2b) = 0

3x[3x - (2a + b)] - (a + 2b) [3x - (2a + b)] = 0

[3x - (2a + b)] [3x - (a + 2b)] = 0

x =  2a + b / 3

or

x= a+ 2b / 3