Question

find the roots of the quadratic equation 9y^2-3y=2



pls i need it
so urgent pls guys

Answer 1

Answer:

How to solve your problem

9

2

−

3

=

2

9y^{2}-3y=2

9y2−3y=2

Factor

1

Move terms to the left side

9

2

−

3

=

2

9y^{2}-3y=2

9y2−3y=2

9

2

−

3

−

2

=

0

Answer 2

Answer:

it can be written as :-

9y²-3y -2 = 0

9y² -6y + 3y -2 = 0

3y(3y-2) +1(3y-2) = 0

( 3y + 1 ) ( 3y - 2 ) = 0

< marquee > < font color="red" > the zeros are -1/3 and +2/3 < /marquee ><marquee><fontcolor="red">thezerosare−1/3and+2/3</marquee

hope it's helpful