Question

find the roots of the quadratic equation and solve it with steps
$6 {x}^{2} - x - 2 = 0$
​

Answer 1

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-find the roots of the quadratic equation

$6 {x}^{2} - x - 2 = 0$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$⟹6 {x}^{2} - x - 2 = 0$

$⟹6 {x}^{2} - 4x + 3x - 2 = 0$

$⟹2x(3x - 2) + 1(3x - 2) = 0$

$⟹(3x - 2)(2x + 1) = 0$

$⟹3x - 2 = 0$

$⟹2x + 1 = 0$

$⟹x = \frac{2}{3}$✓

$⟹x = - \frac{1}{2}$✓

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

Answer:

6x²-x-2=0

6x²-4x+3x-2=0

2x(3x-2)+1(3x-2)=0

(3x-2) (2x+1) =0

3x = 2 ||| 2x = -1

x = 2/3 ||| x = -1/3