Question

find the roots of the quadratic equation by factorisation:2x^2-7x+3=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$2 {x}^{2} - 7x + 3 = 0 \\ 2 {x}^{2} - 6x - x + 3 = 0 \\ 2x(x - 3) - 1(x - 3) = 0$

$(2x - 1)(x - 3) = 0 \\ 2x - 1 = 0 \\ 2x = 1 \\ x = \frac{1}{2}$

$x - 3 = 0 \\ x = 3$