Question

find the roots of the quadratic equation by quadratic formula;4xsquare- 36x+81:0​

Answer 1

Answer:

Answer:$x = \frac{9}{2}$

Answer:$x = \frac{9}{2}$$x = 4$

Answer:$x = \frac{9}{2}$$x = 4$PLEASE FIND THE ANSWER IN THE ATTACHED PIC

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Answer 2

Step-by-step explanation:

1. $4x {}^{2} - 36x + 81 = 0 \\ x = - b + - \sqrt{b { }^{2} } - 4ac \\ \div 2a$
2. $x = - ( - 36) + - \sqrt{} ( - 36) {}^{2} - 4(4)(81) \ \div 2(4)$
3. $x = - ( - 36) + - \sqrt{} ( - 36) {}^{2} - 4(4)(81) \ \div 2(4) \\ \\ x = 36 + - \sqrt{} 1296 - 1296 \div 8 \\ \\ x = 36 + - \sqrt{} 0 \div 8 \\ \\ x = 36 + 0 \div 8 \\ \\ \\ \\ x = 36 \div 2$
4. $x = 36 \div 8$