Question

find the roots of the quadratic equation by the method of compliting square
9x square -16x+ 7​

Answer 1

ROOTS ARE are = $\frac{7}{9}$  and 1

Step-by-step explanation:

9$x^{2}$-16x+7

=9$x^{2}$-9x-7x+7

=9x(x-1)-7(x-1)

=(9x-7)(x-1)

Hence, zeroes are = $\frac{7}{9}$  and 1

HOPE IT HELPS U.

Answer 2

Answer:

1, 7/9

Step-by-step explanation:

$9 {x}^{2} - 16x + 7 = 0$

${(3x)}^{2} - 2(3x)( \frac{8}{3} ) + 7 = 0$

Adding (8/3)² to both sides

${(3x)}^{2} - 2(3x)( \frac{8}{3} ) + { (\frac{8}{3} )}^{2} + 7 = {( \frac{8}{3} )}^{2}$

${(3x - \frac{8}{3}) }^{2} = \frac{64}{9} - 7 = \frac{1}{9}$

Taking square root both sides

$3x - \frac{8}{3} = + - \frac{1}{3}$

$3x = \frac{9}{3} = 3$

or

$3x = \frac{7}{3}$

So we have

$x = 1$

or

$x = \frac{7}{9}$