Question

Find the roots of the quadratic equation by using the quadratic formula : 2xsq-3x-5=0

Answer 1

HERE IS YOUR ANSWER MATE.....;

$eq {}^{n} = > 2 {x}^{2} - 3x - 5 = 0$

$= > 2x {}^{2} + 2x - 5x - 5 = 0$

$= > 2x(x + 1) - 5(x + 1) = 0$

$= > (x + 1)(2x - 5)$

$x = - 1$

$x = \frac{5}{2}$

HOPE IT'S HELPFUL.....:-)

Answer 2

Step-by-step explanation:

given equation 2x²-3x-5

here a=2,b=-3,c=-5

quadratic formula

-b±√b²-4ac/2a

roots are -1 and 1/4