Question

Find the roots of the quadratic equation Find the zeroes of P(x) = 2 x^2+x-6=0

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Answer 1

Answer:

factorisation :

2x^2 + x - 6

2x^2 + 4x - 3x - 6

2x ( x + 2 ) - 3 ( x + 2 )

( x + 2 ) ( 2x - 3 )

zeros of the polynomials :

• x + 2 = 0

x = ( -2 ) ✓

• 2x - 3 = 0

x = 3/2 ✓

___________________________✅

Answer 2

Answer:

2x^2 + x - 6

2x^2 + 4x - 3x - 6

2x ( x + 2 ) - 3 ( x + 2 )

( x + 2 ) ( 2x - 3 )

Step-by-step explanation:

2x^2 + x - 6

2x^2 + 4x - 3x - 6

2x ( x + 2 ) - 3 ( x + 2 )

( x + 2 ) ( 2x - 3 )