Question

Find the roots of the quadratic equation
(i) x²-3x-m(m+3)=0
(ii) 1/2x-3+1/x-5=1​​

Answer 1

Answer:

i) x=-m    OR   x=(m+3)

Step-by-step explanation:

i)

x²-3x-m(m+3)=0

x²-(m+3)x+mx-m(m+3)=0   [-(m+3)+m=-m-3+m=-3]

x(x-(m+3))+m(1-(m+3))=0

(x+m)(x-(m+3))=0

x=-m    OR   x=(m+3)

ii)

Can you write the question with proper brackets or post the photograph instead?